Optimal. Leaf size=213 \[ -\frac{2 (b c-a d) \sqrt{c+d \tan (e+f x)}}{f \left (a^2+b^2\right ) \sqrt{a+b \tan (e+f x)}}-\frac{i (c-i d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a-i b)^{3/2}}+\frac{i (c+i d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a+i b)^{3/2}} \]
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Rubi [A] time = 0.843202, antiderivative size = 213, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.172, Rules used = {3567, 3616, 3615, 93, 208} \[ -\frac{2 (b c-a d) \sqrt{c+d \tan (e+f x)}}{f \left (a^2+b^2\right ) \sqrt{a+b \tan (e+f x)}}-\frac{i (c-i d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a-i b)^{3/2}}+\frac{i (c+i d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (a+i b)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3567
Rule 3616
Rule 3615
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{(c+d \tan (e+f x))^{3/2}}{(a+b \tan (e+f x))^{3/2}} \, dx &=-\frac{2 (b c-a d) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) f \sqrt{a+b \tan (e+f x)}}-\frac{2 \int \frac{\frac{1}{2} \left (-2 b c d-a \left (c^2-d^2\right )\right )-\frac{1}{2} \left (2 a c d-b \left (c^2-d^2\right )\right ) \tan (e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{a^2+b^2}\\ &=-\frac{2 (b c-a d) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) f \sqrt{a+b \tan (e+f x)}}+\frac{(c-i d)^2 \int \frac{1+i \tan (e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{2 (a-i b)}+\frac{(c+i d)^2 \int \frac{1-i \tan (e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{2 (a+i b)}\\ &=-\frac{2 (b c-a d) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) f \sqrt{a+b \tan (e+f x)}}+\frac{(c-i d)^2 \operatorname{Subst}\left (\int \frac{1}{(1-i x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 (a-i b) f}+\frac{(c+i d)^2 \operatorname{Subst}\left (\int \frac{1}{(1+i x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 (a+i b) f}\\ &=-\frac{2 (b c-a d) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) f \sqrt{a+b \tan (e+f x)}}+\frac{(c-i d)^2 \operatorname{Subst}\left (\int \frac{1}{i a+b-(i c+d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{(a-i b) f}+\frac{(c+i d)^2 \operatorname{Subst}\left (\int \frac{1}{-i a+b-(-i c+d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{(a+i b) f}\\ &=-\frac{i (c-i d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{(a-i b)^{3/2} f}+\frac{i (c+i d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{(a+i b)^{3/2} f}-\frac{2 (b c-a d) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) f \sqrt{a+b \tan (e+f x)}}\\ \end{align*}
Mathematica [A] time = 2.12434, size = 220, normalized size = 1.03 \[ \frac{\frac{2 (a d-b c) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) \sqrt{a+b \tan (e+f x)}}-\frac{i (c-i d)^{3/2} \tan ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{-a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{(-a+i b)^{3/2}}+\frac{\sqrt{-c-i d} (d-i c) \tan ^{-1}\left (\frac{\sqrt{-c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{(a+i b)^{3/2}}}{f} \]
Antiderivative was successfully verified.
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Maple [F] time = 180., size = 0, normalized size = 0. \begin{align*} \int{ \left ( c+d\tan \left ( fx+e \right ) \right ) ^{{\frac{3}{2}}} \left ( a+b\tan \left ( fx+e \right ) \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c + d \tan{\left (e + f x \right )}\right )^{\frac{3}{2}}}{\left (a + b \tan{\left (e + f x \right )}\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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